line x+y=7 cuts the circle x^2+y^2-2x-4y-4=0 with center c at a and b if p is on ab such that anglecpa=45 then pa+pb/root2 is

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vibha · Answer

c=(1,2),r=3 prependicular distance from center(1,2) to line x+y-7=0 is 2root2 since point p consist on line ab so using pythagorous theorme pa+pb/root2=root2

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line x+y=7 cuts the circle x^2+y^2-2x-4y-4=0 with center c at a and b if p is on ab such that anglecpa=45 then pa+pb/root2 is

line x+y=7 cuts the circle x^2+y^2-2x-4y-4=0 with center c at a and b if p is on ab such that anglecpa=45 then pa+pb/root2 is

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line x+y=7 cuts the circle x^2+y^2-2x-4y-4=0 with center c at a and b if p is on ab such that anglecpa=45 then pa+pb/root2 is

line x+y=7 cuts the circle x^2+y^2-2x-4y-4=0 with center c at a and b if p is on ab such that anglecpa=45 then pa+pb/root2 is

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