badge image

Enroll For Free Now & Improve your performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

Let z1;z2&z3 represent the vertices of A ;B & C of the triangle ABC respectively in the argand plane such that |z1|=|z2|=|z3|=5 prove that z1sin2A+z2sin2B+z3sin2C=0

3 years ago

Answers : (1)

Arun
24737 Points
							If A-z1, B-z2 and C-z3 are vertices of the triangle, then its centroid G will be (z1+z2+z3)/3Now, |z1|=|z2|=|z3| => the points A,B,C lie on a circle with center as the origin O.Therefore, O is the circumcenter of the triangle.But for an equilateral triangle, the circumcenter coincides with the centroid.Therefore, the centroid of the triangle is Oor(z1+z2+z3)/3 = 0or (z1+z2+z3) = 0Now for an equilateral traingle,Angle A =angle B= angle C =60°Thus We can write the question as Sin2A(z1 + z2 + z3)But we know that(z1 + z2 + z3) =0Hencez1sin2A+z2sin2B+z3sin2C=0
						
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details