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`        Let p(x)=4x2+6x+4 and q(y)= 4y2-12y+25. If x and y satisfy the equation p(x)×q(y)=28find the value of 11y-26x`
6 months ago

Saurabh Koranglekar
3291 Points
```							Dear studentAfter differentiation of two eqn and equating them to zero x = -0.75 and y = 1.5At these values p(x)* q(y) = 28So 11(1.5) -26(-0.75) = 36Regards
```
6 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions