Let p(x)=4x 2 +6x+4 and q(y)= 4y 2 -12y+25. If x and y satisfy the equation p(x)×q(y)=28find the value of 11y-26x

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Saurabh Koranglekar · Answer

Dear student After differentiation of two eqn and equating them to zero x = -0.75 and y = 1.5 At these values p(x)* q(y) = 28 So 11(1.5) -26(-0.75) = 36 Regards

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Let p(x)=4x 2 +6x+4 and q(y)= 4y 2 -12y+25. If x and y satisfy the equation p(x)×q(y)=28find the value of 11y-26x

Let p(x)=4x²+6x+4 and q(y)= 4y²-12y+25. If x and y satisfy the equation p(x)×q(y)=28find the value of 11y-26x

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Let p(x)=4x 2 +6x+4 and q(y)= 4y 2 -12y+25. If x and y satisfy the equation p(x)×q(y)=28find the value of 11y-26x

Let p(x)=4x2+6x+4 and q(y)= 4y2-12y+25. If x and y satisfy the equation p(x)×q(y)=28find the value of 11y-26x

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Let p(x)=4x²+6x+4 and q(y)= 4y²-12y+25. If x and y satisfy the equation p(x)×q(y)=28find the value of 11y-26x