Let g : N → N with g(n) being the product of the digits of n. (a) Prove that g(n) ≤ n for all n ∈ N. (b) Find all n ∈ N, for which n 2 − 12n + 36 = g(n).

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Ajeet Tiwari · Answer

hello students solution to Let g : N &rarr; N with g(n) being the product of the digits of n. (a) Prove that g(n) &le; n for all n &isin; N. (b) Find all n &isin; N, for which n2&minus; 12n + 36 = g(n). is Hope it helps Thankyou

Vikas TU · Answer

Dear student Please refer the clear image of this solution Feel free to ask querry We will happy to help you. Good Luck Cheers

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Let g : N → N with g(n) being the product of the digits of n. (a) Prove that g(n) ≤ n for all n ∈ N. (b) Find all n ∈ N, for which n 2 − 12n + 36 = g(n).

Let g : N → N with g(n) being the product of the digits of n. (a) Prove that g(n) ≤ n for all n ∈ N.
(b) Find all n ∈ N, for which n²− 12n + 36 = g(n).

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Let g : N → N with g(n) being the product of the digits of n. (a) Prove that g(n) ≤ n for all n ∈ N. (b) Find all n ∈ N, for which n 2 − 12n + 36 = g(n).

Let g : N → N with g(n) being the product of the digits of n. (a) Prove that g(n) ≤ n for all n ∈ N.(b) Find all n ∈ N, for which n2− 12n + 36 = g(n).

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Let g : N → N with g(n) being the product of the digits of n. (a) Prove that g(n) ≤ n for all n ∈ N.
(b) Find all n ∈ N, for which n²− 12n + 36 = g(n).