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Grade: 12th Pass

                        

Let f(x) is a polynomial function of degree 5 with leading coefficient equals to one and f(4) = 0 if curves y=|f(x)| and y=f(|x|) are same then f(1) is equal to ?

5 months ago

Answers : (3)

Karan
8 Points
							
f(x)=(x-4)².x.(x+4)1
|f(x)|=f|(x)|
x€R
f(5)=(5-4)1.5.(5+4)²=405
Therefore f of 5 is equal to 405
I hope you got it
5 months ago
Utsav Desai
25 Points
							
@Karan
But how do we come to know that f(x)=(x-4)².x.(x+4)1. That is the main doubt with me. Other websites are also giving same solutions, but no one is explaining why...
5 months ago
Vikas TU
13786 Points
							
Dear student 
This is an example of five degree polynomial ,,,,,,,,,,,
Hope you will understand ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
5 months ago
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