Let a and b be the roots of the equation x^2+x+1=0. The equation whose roots are a^19, b^7 is. A. x^2-x-1=0. B. x^2-x+1=0. C. x^2+x-1=0. D. x^2+x+1=0.

Question

Arun Kumar · Answer

Hello Student,

ab=1, a+b=-1

a=1e^(2pi/3)

b=1e^(-2pi/3)

a^19b^7=1

a^19+b^7=-1

=>x^2+x+1
from above analysis , x^2+x+1 is the correct answer

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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Let a and b be the roots of the equation x^2+x+1=0. The equation whose roots are a^19, b^7 is. A. x^2-x-1=0. B. x^2-x+1=0. C. x^2+x-1=0. D. x^2+x+1=0.

Let a and b be the roots of the equation x^2+x+1=0. The equation whose roots are a^19, b^7 is. A. x^2-x-1=0. B. x^2-x+1=0. C. x^2+x-1=0. D. x^2+x+1=0.

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Let a and b be the roots of the equation x^2+x+1=0. The equation whose roots are a^19, b^7 is. A. x^2-x-1=0. B. x^2-x+1=0. C. x^2+x-1=0. D. x^2+x+1=0.

Let a and b be the roots of the equation x^2+x+1=0. The equation whose roots are a^19, b^7 is. A. x^2-x-1=0. B. x^2-x+1=0. C. x^2+x-1=0. D. x^2+x+1=0.

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