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Grade: 12th pass
        
in the chapter series and sequence following is the question: Find the sum of 1 + 2/2 + 3/22 + 4/23 + …. to n terms
one month ago

Answers : (1)

Vikas TU
8447 Points
							
Dear student 
S =  1 + 2/2 + 3/22 + 4/23 + …. to n/(2n-1) terms..................1
S/2 = 1/2 + 2/22 + 3/23 + 4/24 + …. to n/2n terms.....................2 
Subtract 1 – 2 
S – S/2 = 1+ ½ + 1/22 + ….............. 1/2n-1  + n/2n
This is GP. 
Put the sum of GP formula 
S/2 = 2(2n – 1) / 2n + n/ 2
S = 4 – 2/2n  (n+2)
 
 
 
one month ago
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