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In how many ways can a pack of 52 cards be

(i) divided equally among four players in order

(ii) formed into 4 sets, into 4 groups of 13 cards each.

(iii) In 4 sets, three of them having 17 cards each and the fourth just 1 card?

Amit Saxena , 10 Years ago
Grade upto college level
anser 2 Answers
Navjyot Kalra

Last Activity: 10 Years ago

Hello Student,
Please find the answer to your question
KEY CONCEPT: If 4n different things are to be equally distributed amongst 4 persons the numbers of ways are 4n! /(n!)4 but if 4n things are to form 4 equal groups then the
numbers of ways are (4n!) / (n!)4 x 4!
(i) Number of ways of dividing 52 cards equally among 4 players = 52! / (13!)4
(ii) Numbers of ways to form 4 groups of 13 cards each = 52! / (13!)4 x 4!
(iii) Number of ways to form 4 sets, three of them having 17
Cards each and fourth just 1 card = 52! / (17!)3 x 3! X 1!

Thanks
navjot kalra
askIITians Faculty

Rishi Sharma

Last Activity: 4 Years ago

Dear Student,
Please find below the solution to your problem.

KEY CONCEPT: If 4n different things are to be equally distributed amongst 4 persons the numbers of ways are 4n! /(n!)4 but if 4n things are to form 4 equal groups then the
numbers of ways are (4n!) / (n!)4 x 4!
(i) Number of ways of dividing 52 cards equally among 4 players = 52! / (13!)4
(ii) Numbers of ways to form 4 groups of 13 cards each = 52! / (13!)4 x 4!
(iii) Number of ways to form 4 sets, three of them having 17
Cards each and fourth just 1 card = 52! / (17!)3 x 3! X 1!

Thanks and Regards

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