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`        In an acute angled triangle PQR,angle PQR=45 degree.Prove that (PR)2=(PQ)2+(QR)2-4ar(trianglePQR).`
2 years ago

ATHARV DEO
11 Points
```							construct PN perpendicular to QRin triangle PNQ, angle Q=45so QN=PNPQ^2+QR^2-4*areaPQR=PN^2+QN^2+(QN+NR)2-4*0.5*QR*PN=2PN^2+PN^2+NR^2+2*PN*NR-2*QR*PN=2PN^2+PR^2+2PN.NR-2(PN+NR)*PN=2PN^2-2PN^2+2PN*NR-2PN*NR+PR^2
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions