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If w is complex cube root of unity ,show that 1) (2+w+w square)power 3-(1-3w+w square) power 3=65
As we know1+ w+ w2 = 0& w3 =1We have to use only these two formulas to find theanswer-(1+ 1+w+w2)3 - (1+w2 - 3w)3(1+0)3 - (-w - 3w)31 - (-64 w3)1+ 64= 65Hence provedHope it helps
Take n terms of an AP for both Numerator and denominator. Cancel all the common terms on both sideDivide both side Numerator and denominator by 2.Equate coefficient of 'd' in numerator and denominator to 5&20 respectively. Solvefor p&q.
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