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if the roots of the equation x^2+3x+2=0 and x^2-x+lambda =0 are in the same ratio then the value of lambda is
Roots of X2+3x+2 be X=-1 and X= -2 So ratio will be 1/2 Assume roota of x2-x+ lambda be a and 2a Then a+2a = -(-1/1)= 1So 3a= 1 So a=1/3And products of roots a*2a = lambda/1So lambda =2a^2 =2/9
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