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`        if the root of the equation x²+px+q=0 differ from roots of equation x²+qx+p=0 by same quantity then A)p+q+1=0.          B)q+p+2=0C)p+q+4=0.           D)None Of These ?`
2 years ago

```							Let a and b be the roots for first quadratic and c and be the roots for second.if the root of the equation x²+px+q=0 differ from roots of equation x²+qx+p=0then,a – b = c – d = kNow difference of the roots in terms of sum of roots and prodduct of roots is:=> |a-b| = root((a+b)^2 – 4ab))and similarly,|c-d| = root((c+d)^2 – 4cd))putting the values we get,root((-p)^2 – 4q)) – root((-q)^2 – 4p)) = kNow k could be any assume it be zerothen,root((-p)^2 – 4q)) – root((-q)^2 – 4p)) = 0solving we get,p + q + 4 = 0
```
2 years ago
```							The given condition implies that the difference of the roots is the same for both quadratics. Hence  which is p, q are unequal leads to p+q+4 = 0
```
2 years ago
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