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`        If the coefficient of x3 in the expansion of (1+x)n is 20 find n and n is in power`
11 months ago

Arun
14889 Points
```							 Dear Priyansh General term = nCr x^rNowx³ coefficient = 20r = 3 NownC3 = 20Hencen!/3!*(n-3)! = 20n(n-1)(n-2) = 120(n²-n)(n-2) = 120n³ - 3n² +2n -120 = 0Now find n RegardsArun (askIITians forum expert)
```
11 months ago
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## COUPON CODE: SELF10

### Course Features

• 731 Video Lectures
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions