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if n(A)=3 n(B)=5 then the number of non injective mappings possible from B to A is

if n(A)=3 n(B)=5 then the number of non injective mappings possible  from B to A is

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1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
6 years ago
Hello student,
Each element of B can be mapped on to any of 3 elements of A
Therefore total number of non-injective mappings from B to A is
=3*3*3*3*3=243
Thanks and Regards
Shaik Aasif
askIITians faculty

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