if log x/2a+3b-5c = log y/2b+3c-5a = log z/2c+3a-5b then how is it equal to (log x +log y+ log z)/0??And if so then why is (log x +log y+ log z)/0 not considered undefined instead (log x +log y+ log z)/0 implies log xyz =0. Why??

Question

if log x/2a+3b-5c = log y/2b+3c-5a = log z/2c+3a-5b then how is it equal to (log x +log y+ log z)/0??And if so then why is (log x +log y+ log z)/0 not considered undefined instead (log x +log y+ log z)/0 implies log xyz =0. Why??

Anish Singhal · Answer

Please use brackets in log its not clear what is the exact expression

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if log x/2a+3b-5c = log y/2b+3c-5a = log z/2c+3a-5b then how is it equal to (log x +log y+ log z)/0??And if so then why is (log x +log y+ log z)/0 not considered undefined instead (log x +log y+ log z)/0 implies log xyz =0. Why??

if log x/2a+3b-5c = log y/2b+3c-5a = log z/2c+3a-5b then how is it equal to (log x +log y+ log z)/0??And if so then why is (log x +log y+ log z)/0 not considered undefined instead (log x +log y+ log z)/0 implies log xyz =0. Why??

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if log x/2a+3b-5c = log y/2b+3c-5a = log z/2c+3a-5b then how is it equal to (log x +log y+ log z)/0??And if so then why is (log x +log y+ log z)/0 not considered undefined instead (log x +log y+ log z)/0 implies log xyz =0. Why??

if log x/2a+3b-5c = log y/2b+3c-5a = log z/2c+3a-5b then how is it equal to (log x +log y+ log z)/0??And if so then why is (log x +log y+ log z)/0 not considered undefined instead (log x +log y+ log z)/0 implies log xyz =0. Why??

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