if log 3 (x 3 -x 2 -x+1)-log 3 (x-1)-log 3 (x+1) = 2 then x =? 1 -1 10 none

Question

Hasan Naqvi · Answer

10

ng29 · Answer

its quite easy anwer is all of these 1 , -1 and 10 we have to just use properies of log so we compare both sides we get log(x 3 -x 2 -x-1/x 2 -x) = 2 log3 we get cubic equation whose roots can be find easily x 3 -10x 2 -x+10=0 APPROVE IF USEFUL

grenade · Answer

@ ng29 + 1 and – 1 are incorrect answer because in the initial expression on substituting + and – 1 tending towards infinity

grenade · Answer

corre

grenade · Answer

10 is the correct answer approve if useful

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if log 3 (x 3 -x 2 -x+1)-log 3 (x-1)-log 3 (x+1) = 2 then x =? 1 -1 10 none

if log₃ (x³-x²-x+1)-log₃(x-1)-log₃(x+1) = 2 then x =?

1

-1

10

none

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if log 3 (x 3 -x 2 -x+1)-log 3 (x-1)-log 3 (x+1) = 2 then x =? 1 -1 10 none

if log3 (x3-x2-x+1)-log3(x-1)-log3(x+1) = 2 then x =? 1 -1 10 none

5 Answers

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if log₃ (x³-x²-x+1)-log₃(x-1)-log₃(x+1) = 2 then x =?

1

-1

10

none