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if log 3 (x 3 -x 2 -x+1)-log 3 (x-1)-log 3 (x+1) = 2 then x =? 1 -1 10 none
10
its quite easy anwer is all of these 1 , -1 and 10we have to just use properies of log so we compare both sideswe get log(x3-x2-x-1/x2-x) = 2 log3we get cubic equation whose roots can be find easilyx3-10x2-x+10=0 APPROVE IF USEFUL
@ ng29 + 1 and – 1 are incorrect answer because in the initial expression on substituting + and – 1 tending towards infinity
corre
10 is the correct answer approve if useful
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