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if log 3 (x 3 -x 2 -x+1)-log 3 (x-1)-log 3 (x+1) = 2 then x =? 1 -1 10 none

if log3 (x3-x2-x+1)-log3(x-1)-log3(x+1) = 2 then x =?
  1. 1
  2. -1
  3. 10
  4. none

Grade:9

5 Answers

Hasan Naqvi
97 Points
6 years ago
10
ng29
1698 Points
6 years ago
its quite easy anwer is all of these 1 , -1 and 10
we have to just use properies of log so we compare both sides
we get log(x3-x2-x-1/x2-x) = 2 log3
we get cubic equation whose roots can be find easily
x3-10x2-x+10=0
 
APPROVE IF USEFUL
grenade
2061 Points
6 years ago
@ ng29 + 1 and – 1 are incorrect answer because in the initial expression on substituting + and – 1 tending towards infinity
grenade
2061 Points
6 years ago
corre
grenade
2061 Points
6 years ago
10 is the correct answer
 
approve if useful

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