If c0, 4a+c the root of the equation f(x)=ax^2 -bx +c=0, lie in which interval.

Question

If c>0, 4a+c the root of the equation f(x)=ax^2 -bx +c=0, lie in which interval.

Vikas TU · Answer

That depends on the options provided. Or U need to tell more. this data is insufficient. . At this point it is given that c is positive and f(2) is less than 0. Hence, the graph would be passing through the intecept c and a would be obvious negative as from 4a + c – 2b is less than 0 given and thus the graph would be facing downlwards. Hence the inetrval should be if nothing is given would be, (-infinity,2)

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If c>0, 4a+c the root of the equation f(x)=ax^2 -bx +c=0, lie in which interval.

If c>0, 4a+c
the root of the equation
f(x)=ax^2 -bx +c=0,
lie in which interval.

1 Answers

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If c>0, 4a+c the root of the equation f(x)=ax^2 -bx +c=0, lie in which interval.

If c>0, 4a+cthe root of the equation f(x)=ax^2 -bx +c=0,lie in which interval.

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If c>0, 4a+c
the root of the equation
f(x)=ax^2 -bx +c=0,
lie in which interval.