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If a/(b+c)+b/(c+a)+c/(a+b),then a2/(b+c)+b2/(c+a)+c2/(a+b)=?
LET A/B+C=-1,B/C+A=1,C/A+B=1 will satisfy this equation from above,a= -(b+c),......(1)b=c+a.....(2)c=a+b.....(3) now adding equation1,2,3a+b+c=2ab+c=a....(4) now a2/b+c=a*(a/b+c)=-a......(5) similarly b2/c+a=b...............(6)aandc2/a+b=c.......(7) now adding equaation5,6,7we find desire value(a2/b+c)+( b2/c+a)+(c2/a+b)=-a+b+c...(8) from equaation 4b+c=a put value inequation 8-a+b+c= -a+a=0 hence proved
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