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# If a/(b+c)+b/(c+a)+c/(a+b),then a2/(b+c)+b2/(c+a)+c2/(a+b)=?

4 years ago

abhilash
19 Points

LET A/B+C=-1,B/C+A=1,C/A+B=1 will satisfy this equation

from above,
a= -(b+c),......(1)
b=c+a.....(2)
c=a+b.....(3)

a+b+c=2a
b+c=a....(4)

now a2/b+c=a*(a/b+c)=-a......(5)

similarly b2/c+a=b...............(6)
aand
c2/a+b=c.......(7)

we find desire value
(a2/b+c)+( b2/c+a)+(c2/a+b)=-a+b+c...(8)

from equaation 4
b+c=a

put value inequation 8
-a+b+c= -a+a=0

hence proved

3 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions