 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
If A and B are the roots of the equation x^2+Ax+B=0 then find the minimum value of this equation.
If A and B are the roots of the equation x^2+Ax+B=0 then find the minimum value of this equation.

```
4 years ago

```							The minimum value of the equation is given by -D/4a.D = A^2-4AB, so -D = 4AB – A^24a = 4, so -D/a=4a = 4AB-A^2/4.Since A and B are the roots, 4AB-A^2 = 0So minimum value of equation is equal to 0
```
4 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions