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If A and B are the roots of the equation x^2+Ax+B=0 then find the minimum value of this equation. If A and B are the roots of the equation x^2+Ax+B=0 then find the minimum value of this equation.
The minimum value of the equation is given by -D/4a.D = A^2-4AB, so -D = 4AB – A^24a = 4, so -D/a=4a = 4AB-A^2/4.Since A and B are the roots, 4AB-A^2 = 0So minimum value of equation is equal to 0
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