Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If 1, w and w^2 is cube root of unity then show (1-w+w^2)(1-w^2+w^4)(1-w^4+w^8)......to n factors=2^2n.

If 1, w and w^2 is cube root of unity then show (1-w+w^2)(1-w^2+w^4)(1-w^4+w^8)......to n factors=2^2n.

Grade:11

1 Answers

Shailendra Kumar Sharma
188 Points
3 years ago
as we know 1-w+w2= 0
so 1+w2 =-w, so it will be -2w
take 1-w2+w4
=1-w2+w3*w=1-w2+w
(-w2-w2)=-2w2

Next term is 1-w4+w8 =( 1-w+w2)
so the trend will repeat 
Now (1-w+w2)X1-w2+w4 =(-2w)*(-2w2) =2^2
similarly for n terms it will be 2^2n

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free