If 1/1^2 + 1/2^2 + 1/3^2 + ........ upto infinity = pi^/6, then 1/1^2 + 1/3^2 + 1/5^2 +..... =

1/1^2 + 1/2^2 + 1/3^2 + ........ upto infinity = pi^n ...(1)...(n=1/6 or whatever, not mentioned in the question)

Let [1/1^2 + 1/3^2 + 1/5^2 + ........ upto infinity]= S_o ...(2)
(1)-(2)=1/2^2 + 1/4^2 + 1/6^2 + ........ upto infinity = pi^n – S_o
=(1/2²)[1/1^2 + 1/2^2 + 1/3^2 + ........ upto infinity ]=pi^n – So
=(1/2²)[pi^n]=pi^n-S_o
Solve the equation to get the value of S_oin terms of pi^6