0

Guest

Courses New

If 1/1^2 + 1/2^2 + 1/3^2 + ........ upto infinity = pi^/6, then 1/1^2 + 1/3^2 + 1/5^2 +..... =

If 1/1^2 + 1/2^2 + 1/3^2 + ........ upto infinity = pi^/6, then 1/1^2 + 1/3^2 + 1/5^2 +..... =

Grade:11

1 Answers

Ravi
askIITians Faculty 69 Points
9 years ago
1/1^2 + 1/2^2 + 1/3^2 + ........ upto infinity = pi^n ...(1)...(n=1/6 or whatever, not mentioned in the question)

Let [1/1^2 + 1/3^2 + 1/5^2 + ........ upto infinity]= So ...(2)
(1)-(2)=1/2^2 + 1/4^2 + 1/6^2 + ........ upto infinity = pi^n – So
=(1/22)[1/1^2 + 1/2^2 + 1/3^2 + ........ upto infinity ]=pi^n – So
=(1/22)[pi^n]=pi^n-So
Solve the equation to get the value of Soin terms of pi^6

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More