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If 0÷0=5 then x^2-9÷x-3=? at x=3 then which option is correct ?1.five solution substituting x=3 then 9-9÷3-3=0÷0=5 2.not defined 0÷0 3.six solution x^2-9=x^2-3^2=(x-3)(x+3) then Q becomes x+3 4.real numbers for me 0÷0 is R
If 0÷0=5 then x^2-9÷x-3=? at x=3 then which option is correct ?1.five solution substituting x=3 then 9-9÷3-3=0÷0=5  2.not defined 0÷0  3.six solution x^2-9=x^2-3^2=(x-3)(x+3) then Q becomes x+3  4.real numbers for me 0÷0 is R

```
4 years ago

```							For me 0÷0 will be real number if and only if 0=0 proof let 0÷0=x if  we put x=1;2;3;4.......n then we get 0=0 it means x belongs to real number
```
4 years ago
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