If 0÷0=5 then x^2-9÷x-3=? at x=3 then which option is correct ?1.five solution substituting x=3 then 9-9÷3-3=0÷0=5 2.not defined 0÷0 3.six solution x^2-9=x^2-3^2=(x-3)(x+3) then Q becomes x+3 4.real numbers for me 0÷0 is R

sharukh qureshi , 9 Years ago

Grade 12