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how to solve the inequality 1) (x+2)(x+2)(x-3)/(x-2)(x-4)(x-6)>=0 here the factor (x+2) is repeated twice. 2) (x+1)(x-1)/(x+1)(x+2)(x+3) here numarator and denominator has a common factor,can we cancell it

how to solve the inequality  
 1) (x+2)(x+2)(x-3)/(x-2)(x-4)(x-6)>=0
here the factor (x+2) is repeated twice.
 2) (x+1)(x-1)/(x+1)(x+2)(x+3)
here numarator and denominator has a common factor,can we cancell it

Grade:12th pass

1 Answers

Sunil Raikwar
askIITians Faculty 45 Points
9 years ago
  1. such types of questions are solved with the help of wavy curve. In wavy curve put the roots of equation on no line & draw the curve whinch changes its sign alternately if roots is repeated then sign is also repeated.
+ + _ + _ +
- 2 2 3 4 6
  1. we can’t cancel x+1 from x+1 untill we have not conferm that x not equal to -1 because we can’tcancel zero from zero.
Thanks & Regards
Sunil Raikwar
askIITians Faculty

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