MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 9
        
Highest comman factor of (21m+4) and (14m+3) is? [where m belongs to N]
11 months ago

Answers : (1)

Arun
22984 Points
							
Dear student
 
please post the optio s tooas these question require options too to check. I am solving this as a question which is similiar to this sokved by me in past
 
m = natural number.   Two numbers:  N1: 21 m + 4,     N2:   14 m + 3
1)  N2 is always odd, as 14m is even and 3 is odd. So option a is incorrect. N2 is not divisible by 2. So  2 cannot be HCF.
2)  N1 = 21 m + 4 ,      N2 = 14 m + 3
     Add N1 + N2 =  35 m + 7 = 35 m + 5 + 2
    If N1 and N2 are divisible by 5, then N1+N2 must be divisible by 5.
     But we see clearly that N1+N2 is not divisible by 5.
3)    N1 = 21 m + 4     N2 = 14 m + 3
       N1 - N2 = 7 m + 1 
       3 N2 - 2 N1 = 42 m + 9 - 42 m - 8 = 1
  
    If N1 and N2 are both divisible by 9, then  3 N2 - 2 N1 should be divisible by 9 or it should be 0.  So 9 is not the HCF.
 
11 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details