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# for what values of a and b lim x?8 ((x²+1)÷(x+1))-ax-b =0

7 years ago
limx-$((x^2+1)/(x+1))-ax-b =0$-

= x-ax-b
if a=1 and b=0 this will be zero , and hence a=1 and b=0 is answer.

7 years ago
`limx-$((x^2+1)/(x+1))-ax-b =0$-=x-ax-bif a=1 and b=0 this will be zero , and hence a=1 and b=0 is answer.`
7 years ago
$lim\frac{x^2+1}{x+1}=x$
limx-$((x^2+1)/(x+1))-ax-b =0$-

=limx-ax-b
if a=1 and b=0 this will be zero , and hence a=1 and b=0 is answer

Sher Mohammd,
B.tech IIT Delhi