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`         Find the values of a, if ax2 – 4x + 9 = 0 has integral roots `
3 years ago

Vikas TU
11138 Points
```							For the roots to be integer the D that is the discriminat of the quadratic should be a perfect square and a= 1 with b and c should be integers which is howevr fulfilling the condtion.Thereofre for a =1 the eqn. would have integera roots.
```
3 years ago
Abhinav Kumar
16 Points
```							Let a=1/b, so the given equation becomesx²-4bx+9b=0.This equation has integral roots if b is an integer. So discrimnant equals to 16b²-3band it must be a perfect square. Let k²=16b²-36b+81/4-81/4.So, k²=(4b-9/2) ²-81/4After solving we will get: (8b-9-2k) (8b-9+2k) =1×81, 3×27, 9×9, 27×3, 81×1It is satisfying only 81×1, 3×27.So b=3, -4. By this way we can conclude a=1/3, -1/4
```
one year ago
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
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• Previous Year Exam Questions