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Find the Locus of mid-point of line segment intercepted between real and imaginary Axis, by the line a’ z + a z’ +b =0 where b is real parameter and a is fixed complex number such that Re(a) and Im(z) is not equal to zero . a’ and z’ are complex conjugate of a and z respectively .

saurabh , 10 Years ago
Grade 12th pass
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
Hello Student,
Please find solution to your question below

a’z + az + b = 0
Let z = x + iy
z’ = x – iy
Let a = c + id, where c & d are real numbers.
a’ = c – id
Put in the equation, we have
(c – id)(x + iy) + (c + id)(x – iy) + b = 0
(cx + dy + i(cy - dx)) + (cx + dy + i(-cy + dx)) + b = 0
2cx + 2dy + b = 0
Let the mid – point of the line segment to be (h, k)
Line intersect the axis at
Real Axis:
y = 0
x = \frac{-b}{2c}
Imaginary Axis:
x = 0
y = \frac{-b}{2d}

h = \frac{-b}{4c}
k = \frac{-b}{4d}
ch = dk
h\rightarrow x, k\rightarrow y
y = \frac{c}{d}x



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