MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
find the least natural no having 24 divisors.
(ques from permutation and combination)
one year ago

Answers : (1)

moumi roy
91 Points
							
the smallest number  may be 360.let Q be the needed number and the total devisors are(a+1)(b+1)..(n+1)=24.as 24 can only be broken inti smaller numbers in only a few waylike 3*2*2*2=4*3*2=6*4=6*2*2=24.so the snallest prime will be out of all 360 as  2^(2-1)*3^(3-1)*5^(2-1)=2^3*3^3*5=360
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details