Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Find the equation of the straight line passing through the point( 1, 2, 3 )to intersect the straight line X + 1 = 2(y-2)=z+4 and parallel to the plane X + 5 y + 4 z = 0`
10 months ago

Deepak Kumar Shringi
4397 Points
```							to fine the vector parellel to the line do cross product of the normal vector to the plane and made one more vector by using given point and one point from the given line
```
8 months ago
Rajat
213 Points
```							Let the point of intersection be,(k-1, k/2+2, k-4)Show the direction ratio of the required line=(k-1-1, k/2+2-2, k-3-4) = (k-2, k/2, k-7) The direction ratio of the normal to the given plane = ( 1, 5, 4)the normal to the given plane is perpendicular to the required line since the required line is parallel to the given plane.So, (1)(k-2)+(5)(k/2)+(4)(k-7) = k-2+5k/2+4k-28=15k/2-30=0 ; So, k = 4The point of intersection is ( 3, 4, 0)Eqn of the line is ;(x-1)/(3-1)=(y-2)/(4-2)=(z-3)/(0-3)Or, (x-1)/2= (y-2)/2 = (z-3)/(-3)
```
8 months ago
Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions