#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3i+2j-2k

Latika Leekha
6 years ago
The position vector of A (1, 2, 3) is i + 2j + 3k.
Hence, the vector equation of the line passign through A and parallel to the vector 3i+2j-2k is given by
$\vec{}$a = i + 2j + 3k + $\lambda }$( 3i+2j-2k).
( Vectors have been denoted by bold letters)
Thanks & Regards
Latika Leekha