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Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3i+2j-2k

samrat , 10 Years ago
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anser 2 Answers
Latika Leekha

Last Activity: 10 Years ago

The position vector of A (1, 2, 3) is i + 2j + 3k.
Hence, the vector equation of the line passign through A and parallel to the vector 3i+2j-2k is given by
\vec{}a = i + 2j + 3k + \lambda }( 3i+2j-2k).
( Vectors have been denoted by bold letters)
Thanks & Regards
Latika Leekha
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surya

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