Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3i+2j-2k

Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3i+2j-2k

Grade:

2 Answers

Latika Leekha
askIITians Faculty 165 Points
6 years ago
The position vector of A (1, 2, 3) is i + 2j + 3k.
Hence, the vector equation of the line passign through A and parallel to the vector 3i+2j-2k is given by
\vec{}a = i + 2j + 3k + \lambda }( 3i+2j-2k).
( Vectors have been denoted by bold letters)
Thanks & Regards
Latika Leekha
askIITians Faculty
surya
40 Points
6 years ago

Surya

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free