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find the equation of a tangent line to ellipse 9x^2+25y^2=225 at x=3
put x=3 in eq. of the ellipse9(9)+25y2=22581+25y2=22525y2=144y2=144/25y=12/5so the touching point is (3,12/5)eq. of the ellipse can be written as x2/25 +y2/9 =1noq eq of the tangent to the ellipse at point (3,12/5) is3x/25 +12y/45=127x+60y=225 Ans.Thanks & RegardsRinkoo GuptaAskIITians Faculty
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