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Find the distance of the point (2,5) from the line 3x+y+4=0 measured parallel to the line having slope 3/4

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3 years ago

Arun
25768 Points
```							Dear Dharmik The parallel line has slope m=(3/4) and passes by (2,5) y-5=(3/4) (x-2) 4y-20= 3x-6 4y =3x+14 3x=4y-14 This line intercepts to line 3x+y+4=0 when (4y-14) +y+4=0 5y= 10 y=2 x=(8-14)/3 = -2 thus, distance is from (2,5) to (-2,2) D= sqrt ( 2-(-2)) ^2 + (5-2)^2 D= sqrt (16+9) = sqrt25 =5  RegardsArun (AskIITians forum expert)
```
3 years ago
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