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`        Find range of the function f(X)=|x-1|+|x-2|+.........|x-100| and discuss about graph of f(X)`
one year ago

2042 Points
```							Actually the least value of |x-a1|+|x-a2|+.....+|x-a2n| such that a1, a2,...,a2n are in ascending order is attained at x belonging to [an, an+1]So least value of above expression is attained at 50.So it's value at 50 is 2(1+2+...+49)+50= 2500So range is [2500, infinty]
```
one year ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions