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Grade 10Algebra

Evaluate
secθcosec(90 –θ)-tanθcot(90-θ)+sin255+ sin235
tan10tan20tan60tan70tan80

Profile image of Rahul Kumar
10 Years agoGrade 10
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1 Answer

Profile image of Shubham Kamleshbhai Patel
10 Years ago
cosec(90° – θ) = sec θ
cot(90° – θ) = tan θ
sin2 (90° – θ) = cos2 θ
Therefore,
sec2 θ – tan2 θ + sin2 55° + sin2 35°
=> (1 + tan2 θ) – tan2 θ + cos2 35° + sin2 35°
=> 1 + 1
=> 2
 
I hope u understood the answer.......

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