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(x–b)(x–c) = x2–11x+a …(1)
b + c = 11
bc=a
(x–a)(x–d)=x2–14x+2a …(2)
b + d = 14
bd = 2a
Solving (1) and (2) equations,
B=8, c =3, d=6 and a = 24.
Thanks & Regards,
Vasantha Sivaraj,
askIITians faculty
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