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`        coefficient of x 2009 in the expansion of (1+x+x^2+x^3+x^4)^1001(1-x)^1002`
3 months ago

## Answers : (1)

1670 Points
```							the ques is not clear so kindly post a picture as well. however, i will try to answer the ques as is.(1+x+x^2+x^3+x^4)^1001(1-x)^1002=[(1+x+x^2+x^3+x^4)(1-x)]^1001(1-x)^1= (1 – x^5)^1001*(1-x)= (1 – x^5)^1001 – x(1 – x^5)^1001in (1 – x^5)^1001, x^2009 cannot occur since 2009 is not divisible by 5.in x(1 – x^5)^1001, to find coeff of x^2009, we need to find coeff of x^2008 in (1 – x^5)^1001, which will be zero since 2008 is not divisible by 5.hence coeff is zero.kindly approve :)
```
3 months ago
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• 101 Video Lectures
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions