An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at
random without replacement from the urn. The probability that the three balls have different colours is -

Question

SHAIK AASIF AHAMED · Answer

Total number of ways of drawing 3 balls out of 9 is 9c 3 =84 Number of ways of drawing so that balls are of different colours is (3c 1 )(4c1)(2c 1 )=24 Therefore probability is =24/84=2/7. Thanks and Regards Shaik Aasif askIITians Faculty

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An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is -

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at
random without replacement from the urn. The probability that the three balls have different colours is -

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An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is -

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is -

1 Answers

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Other Related Questions on Algebra

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An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at
random without replacement from the urn. The probability that the three balls have different colours is -