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a2/(b+c) +b2/(c+a) +c2/(a+b)=0 then prove that a/(b+c) +b/(c+a) +c/(a+b) =1
a2/(b+c) +b2/(c+a) +c2/(a+b)=0 then prove that a/(b+c) +b/(c+a) +c/(a+b) =1

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2 months ago

2074 Points
```							Let a/(b+c) +b/(c+a) +c/(a+b)= kMultiply both sides by a+b+c to get[a2/(b+c)+a] + [b2/(c+a)+b] + [c2/(a+b)+c] = k(a+b+c)Or a2/(b+c) +b2/(c+a) +c2/(a+b) + (a+b+c)= k(a+b+c)Or a+b+c= k(a+b+c)Or k= 1 QEDKINDLY APPROVE :))
```
2 months ago
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Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions