Let XA and XB be the quantity of doll A and B respectively.
Max.Z = 3XA + 5XB
Subject to,
XA + XB ≤ 1500 --------------(1)
Let total time per day = T, So, the time taken to produce one doll A = T/2000
Therefore, the time required to produce one doll B = 2T/2000
So, T*XA/2000 + 2T*XB/2000 ≤ T
or, XA + 2XB ≤ 2000 -------------(2)
XB ≤ 600 ------------(3)
XA, XB ≥ 0 ------------(4)