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A square is inscribed in the circle x^2+y^2-2x+4y-93=0 with its sides parallel to the co-ordinate axes. Find the co-ordinates of its vertices.

Aakash , 11 Years ago
Grade 12th pass
anser 1 Answers
Sher Mohammad

Last Activity: 11 Years ago

(x-1)^2+(y+2)^2=93+1+4=98=(7*sqrt(2))

The vertices are at a distance of 7 units (Half the side) measured in

parallel with x & y axes, from the center (1, -2) of the circle.

Hence the vertex A is (1-7, -2-7) = (-6, -9)

Vertex B is (1+7, -2-7) = (8, -9)

Vertex C is (1+7, -2+7) = (8, 5)

Vertex D is (1-7, -2+7) = (-6, 5)

sher mohammad
b.tech, iit delhi

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