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Let x denote the breadth of the rectangular piece and y denote the length of the rectangular piece of land.now according to the question
since the total fencing available is 3000 m ,therefore
2x + y = 3000or y = 3000 – 2xand the area (A) = xy
therefore A = x (3000 – 2x)
now if we have to enclose certain area then it has to be greater than zero.
Now , x >0 , y > 0 i.e. 3000 – 2x > 0
Which means that 3000 > 2xOr 2x < 3000Or x < 1500
But length should be greater than the breadth i.e. y>x
Which means that 3000 – 2x > x
Or 3000 > 3x ; x < 1000
Now if we see the three bold solution i.e. x < 1000 , x < 1500 and x >0 then on number line we can plot the result as
hence the value of x lies between 0 and 1000or 0 < x < 1000
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