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a, b, c are real and AIs not equal to 0 and the quadratic equation ax square +bx +c=0 has no real roots then which of the following is not always true? A) a+b+c >0B) c(a+b+c) >0C) c(a-b+c)>0D) (a+b+c) (a-b+c)>0

a, b, c are real and AIs not equal to 0 and the quadratic equation ax square +bx +c=0 has no real roots then which of the following is not always true? A) a+b+c >0B) c(a+b+c) >0C) c(a-b+c)>0D) (a+b+c) (a-b+c)>0

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subrat
61 Points
6 years ago
In option A, B, C we cannot comment as we have no clue of sign of a and c.
In option D on simplification we get  (a+c)2 – b2 and b2 – 4ac2 + bx + c=0 are not real). This means b2 > 0. Hence D is the answer.2 – b2 >4ac. This means that (a+c)2 GM on a and c we get (a+c)

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