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Grade: 12th pass
        
65th question
I want answer shsiejdhdghdiskwjgwhhsjdijdjbdbjsjskndbdbjdjsjkskskjxnndjskkxicijdjejwksoidjrnnekwjdjdnwmkskdjdjdmwkskjf
 
one month ago

Answers : (2)

Sanyam Shah
54 Points
							
zk=1+a+a^2....
zk=(1-ak)/(1-a)... Sum of G.P.
zk=1/(1-a)-ak/(1-a)
zk-1/(1-a)=-ak/(1-a)
Apply mod on both the sides of equation:
|zk-1/(1-a)|=|-ak/(1-a)|
|zk-1/(1-a)|
Approve my answer : Pls....
 
one month ago
Vikas TU
11761 Points
							
Dear student 
Please ask only single question in a thread 
It will be easier for us to ans..
Good Luck 
Cheers .............
one month ago
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