dear sir/madam,how to solve this problem?please help.

The number of positive integral solutions of XYZT=210 are

A)256

b)64

c)24

d)120

Dear h v

factorise 210 = 7*5*3*2

XYZT =210

7 can be assign to any X,Y,Z,T in = 4 ways

similerly    5 can be assign to any X,Y,Z,T in = 4 ways

              3 can be assign to any X,Y,Z,T in = 4 ways

              2 can be assign to any X,Y,Z,T in = 4 ways

 so total ways  = 4*4*4*4 =256

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Badiuddin

thanks for the answer