The digits Of a three digit number form a G.P.If we subtract 792 from this number whose digits are written in reverse order .If we increase the middle digit of a given number by 2, then the digits form an A.P.find numbers?

DEar love

let the number are ar²,ar,a

 given   ar²,ar+2 ,a  are in AP

        so 2(ar+2) = ar² +a

             a(r-1)² =4 .............1

and given   ar²*100 + ar*10 +a -792 = a*100 + ar*10 + ar²

                      a(r²-1)=8 .......2

from equation 1 and 2nd

 a=1 ,r=3

so number are   = 931

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