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The digits Of a three digit number form a G.P.If we subtract 792 from this number whose digits are written in reverse order .If we increase the middle digit of a given number by 2, then the digits form an A.P.find numbers?
DEar love
let the number are ar2,ar,a
given ar2,ar+2 ,a are in AP
so 2(ar+2) = ar2 +a
a(r-1)2 =4 .............1
and given ar2*100 + ar*10 +a -792 = a*100 + ar*10 + ar2
a(r2-1)=8 .......2
from equation 1 and 2nd
a=1 ,r=3
so number are = 931
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