drawn from origin are two mutually perpendicular straight lines forming an isosceles triangle together with th straight line 2x+y=a. then the area of the triangle is in terms of 'a'?

(A)a²/2

(B)a²/3

(C)a²/5

(D)none

Dear tejas

length of perpendicular on the line 2x+y=a from the origin is

L = |a|/√5

we know that in right angle triangle mid point of hypotnous is  equidistance from all the vertex.

so length of the base = 2L

so area  = 1/2 *L *2L

             =L² = a²/5

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Can you please tell the rough figure for this question with proper labelling of sides as i am not able to get it