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# drawn from origin are two mutually perpendicular straight lines forming an isosceles triangle together with th straight line 2x+y=a. then the area of the triangle is in terms of 'a'? (A)a2/2(B)a2/3(C)a2/5(D)none

147 Points
11 years ago

Dear tejas

length of perpendicular on the line 2x+y=a from the origin is

L = |a|/√5

we know that in right angle triangle mid point of hypotnous is  equidistance from all the vertex.

so length of the base = 2L

so area  = 1/2 *L *2L

=L2 = a2/5

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