# factorize(x+1)(x+2)(x+3)(x+6)-3x2

Jitender Singh IIT Delhi
7 years ago
Ans:
Hello Student,






mycroft holmes
272 Points
7 years ago
Given expression equals $(x^2+4x+3)(x^2+8x+12)- 3x^2$

Now we have  $3x^2 = 6(x^2+4x+3)-3(x^2+8x+12)+18$

Hence if $A =(x^2+4x+3), B=(x^2+8x+12)$,

the given expression can be written out as AB-6A+3B-18 = (A+3)(B-6)

which on substituting back for A and B equals

$(x^2+4x+6)(x^2+8x+6)$

Both expressions are irreducible over integers and hence you can leave the factorization at this stage