if p+sin²x+cos⁴x. then

a)3\4 ≤ p ≤ 1(how ????)

Dear ajinkya

p=sin²x+cos⁴x

   =1-cos²x + cos⁴x

   = 1-cos²xsin²x

   =1-1/4 sin²2x

for maximum value of P , sin2x =0

P = 1

for minimum value of P  ,sin2x=1

P= 1-1/4

   =3/4

so    3/4 ≤ p ≤ 1

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