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a fxn is defined on[-1,1]and area of sq. is 4. with its vertices at (0,0) and (x,f(x)) then f(x) is...


a fxn is defined on[-1,1]and
area of sq. is 4.
with its vertices at (0,0) and (x,f(x))
then f(x) is...

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear Jauneet

one vertex of square is given (0,0) .then a square of area four can not be formed whose rest three  point  lie in [-1,1]

so such function is not possible,

if (x,f(x) is the vertix of other side of diagonal,and other two vertix can be outside the [-1,1] then square is possible

then length of diagonnal = √{f2(x) +x2}

so area =4 =(digonal)2/2

     4= {f2(x) +x2}/2

 so f(x) =±√(8-x2)

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Regards,
Askiitians Experts
Badiuddin

 

 

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