0

Guest

Courses New

1.X2+x+1=0 X2013+2013x2010 =? 2 Sum of values of a for which (x+a)(2013+x)+1 is a perfect square In a triangle ABC, if inradius=1, circumradius=3, semi perimeter=5 then, a2+b2+c2 /12 =? 4) let (x) be a polynomial of degree five with leading coefficient 252 . if f(2)=3, f(3)=8, f(4)=15,f(5)=24,f(6)=35 then f(1)/252=? 5) in a triangle ABC a=5 b=4 c=3. G is the centroid of triangle. circumradius of triangle GAB is

1.X2+x+1=0
X2013+2013x2010 =?
2 Sum of values of a for which (x+a)(2013+x)+1 is a perfect square

In a triangle ABC, if inradius=1, circumradius=3, semi perimeter=5 then,
a2+b2+c2 /12 =?

4) let (x) be a polynomial of degree five with leading coefficient 252 .
if f(2)=3, f(3)=8, f(4)=15,f(5)=24,f(6)=35 then f(1)/252=?

5) in a triangle ABC a=5 b=4 c=3. G is the centroid of triangle. circumradius of triangle GAB is

Grade:11

1 Answers

Amit Jain
askIITians Faculty 32 Points
10 years ago

1552_96662_Algebra_Polynomials_08 Oct 2013 0143PM_Pramay_1.gif

 

882_96662_Algebra_Polynomials_08 Oct 2013 0143PM_Pramay_2.gif

 

1403_96662_signature.gif

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More